Question Bank NAT • 2 Marks Section 2: Classical Mechanics Special theory of relativity

QB_PH_060: Special theory of relativity

Question Statement

An electron ($m_0 c^2 = 0.511\text{ MeV}$) is accelerated to a speed where $\gamma = 3$. Its kinetic energy in MeV is:
Correct Answer
1.02, 1.03
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $K = (\gamma - 1) m_0 c^2 = (3 - 1)(0.511) = 1.022\text{ MeV}$.
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