Question Bank MCQ • 2 Marks Section 2: Classical Mechanics Central force problem

QB_PH_059: Central force problem

Question Statement

In Rutherford scattering of alpha particles of energy $E$, the differential cross-section $\frac{d\sigma}{d\Omega}$ is proportional to:
(A) \frac{1}{\sin^4(\theta/2)}
(B) \frac{1}{\sin^2(\theta/2)}
(C) \cos^4(\theta/2)
(D) \frac{1}{\cos^2(\theta/2)}
Correct Answer
A
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: Standard Rutherford scattering differential cross-section formula.
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