Question Bank NAT • 2 Marks Section 2: Classical Mechanics Special theory of relativity

QB_PH_038: Special theory of relativity

Question Statement

A particle has total energy $E = 2 m_0 c^2$. What is its speed as a fraction of $c$ ($v/c$), rounded to three decimal places?
Correct Answer
0.864, 0.868
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $\gamma = 2 \implies \sqrt{1 - v^2/c^2} = 1/2 \implies v/c = \sqrt{3}/2 \approx 0.866$.
← Prev (QB_PH_037) Next (QB_PH_039) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and official TCS iON calculator.

Launch CBT Mock Test