Question Bank MCQ • 1 Mark Section 2: Classical Mechanics Special theory of relativity

QB_PH_037: Special theory of relativity

Question Statement

In an inertial frame $S$, particle 1 moves in the $+x$ direction at $0.6c$ and particle 2 moves in $-x$ direction at $0.8c$. The speed of particle 1 relative to particle 2 is:
(A) \frac{35}{37}c \approx 0.946c
(B) 1.4c
(C) c
(D) 0.2c
Correct Answer
A
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $u' = \frac{0.6c + 0.8c}{1 + (0.6)(0.8)} = \frac{1.4c}{1.48} = \frac{35}{37}c$.
← Prev (QB_PH_036) Next (QB_PH_038) →

Practice In Authentic CBT Exam Interface

Test your skills under authentic timed conditions with live scoring and official TCS iON calculator.

Launch CBT Mock Test