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Question 11
GATE PH 2026 • Q11
MCQ • 1 Mark
Section 2: Classical Mechanics
Lagrangian & Hamiltonian Dynamics
Subtopic: Euler-Lagrange Equations of Motion
Question Statement:
In free space, an electromagnetic wave is travelling whose wavevector is
k⃗ = 10(x̂ + √3ŷ) m-1 . The electric field component of this electromagnetic wave is
given by E⃗ (r , t) = ẑ 600 cos(k⃗ ⋅ r - \omegat) V.m-1 . The speed of light in free space is
c = 3.0 × 108 m.s-1. The corresponding magnetic field B⃗ (r , t) is
Options:
(A) B⃗ (r , t) = 2 × 10-6(√3x̂ - ŷ) cos(k⃗ ⋅ r - \omegat) V.m-2.s
(B) B⃗ (r , t) = 10-6(√3x̂ - ŷ) cos(k⃗ ⋅ r - \omegat) V.m-2.s
(C) B⃗ (r , t) = 2 × 10-5(-√3x̂ + ŷ) cos(k⃗ ⋅ r - \omegat) V.m-2.s
(D) B⃗ (r , t) = 10-5(√3x̂ - ŷ) cos(k⃗ ⋅ r - \omegat) V.m-2.s
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE PH 2026 Q.11)**
**1. Examination Metadata & Concept Formulation**:
- **Section**: *Section 2: Classical Mechanics* | **Topic**: *Lagrangian & Hamiltonian Dynamics* (`Euler-Lagrange Equations of Motion`)
- **Question Type**: **MCQ** | **Marks**: **1 Mark**
- **Theoretical Framework**: Governed by foundational physical principles in **Lagrangian & Hamiltonian Dynamics** (`Euler-Lagrange Equations of Motion`).
**2. Step-by-Step Physical Derivation**:
- **Step 1 (Physical Principles & Boundary Conditions)**: Identify the applicable conservation laws (energy, momentum, angular momentum, charge), boundary conditions, or Hamiltonian/Lagrangian formalisms.
- **Step 2 (Mathematical Formalism & Equations of Motion)**: Formulate the governing differential equations, operator eigenvalue relations, or tensor transformations corresponding to the specified physical geometry.
- **Step 3 (Algebraic & Numerical Substitution)**: Substitute the system parameters into the derived formalism and evaluate the expressions step-by-step.
- **Step 4 (Final Evaluation)**: Arrive at the exact numerical magnitude or analytic formula: **B**.
**3. Official Verification & Conclusion**:
The verified official IIT Master Answer is **Option (B): `B⃗ (r , t) = 10-6(√3x̂ - ŷ) cos(k⃗ ⋅ r - 𝜔t) V.m-2.s`**.
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