GATE PH 2025 • Q47 MSQ • 2 Marks

Section 7: Solid State Physics

Dielectric, Magnetic Properties & Superconductivity

Subtopic: Meissner Effect, Type I and Type II Superconductors

Question Statement:

Which of the following option(s) is/are correct for a Type I superconductor?

Options:

  • (A) The phase transition to the normal state in the absence of a magnetic field is o f second order
  • (B) With increase in temperature, the critical magnetic field decreases linearly to zero
  • (C) Below the critical temperature, the entropy in the superconducting state is less than that in the normal state
  • (D) The phase transition to the normal state in the presence of a magnetic field is of first order

Official Answer Key:

A;C;D

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2025 Q.47)** **1. Thermodynamics of Type I Superconductors**: - Critical magnetic field relation: $B_c(T) = B_c(0)[1 - (T/T_c)^2]$. **2. Detailed Analysis of Statements (MSQ)**: - **(A) Second-order phase transition at $B = 0$ [TRUE]**: - In zero external magnetic field ($B = 0$), the latent heat $L = -T \frac{B_c}{\mu_0}\frac{dB_c}{dT} = 0$. - However, the specific heat exhibits a finite jump discontinuity at $T_c$ (Rutgers formula $\Delta C = \frac{T_c}{\mu_0}\left(\frac{dB_c}{dT}\right)^2 > 0$). Hence, it is a second-order phase transition. - **(B) False**: $B_c(T)$ decreases parabolically, not linearly. - **(C) Entropy of superconducting state is less than normal state [TRUE]**: - Below $T_c$, electrons condense into macroscopic coherent Cooper pairs, reducing disorder ($S_{\text{super}} < S_{\text{normal}}$). - **(D) First-order phase transition in the presence of magnetic field [TRUE]**: - When $B \ne 0$, the transition occurs at a reduced temperature with non-zero critical field $B_c(T) > 0$. - The entropy discontinuity $\Delta S = S_n - S_s = -\frac{B_c}{\mu_0}\frac{dB_c}{dT} > 0$ produces a non-zero latent heat $L = T\Delta S > 0$, making it a first-order phase transition. **3. Official Verification**: The verified official IIT answer is **Options (A), (C), and (D)** (`['A', 'C', 'D']`).

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