GATE PH 2025 • Q29 MSQ • 1 Mark

Section 2: Classical Mechanics

Special theory of relativity

Subtopic: Relativistic Kinematics & Doppler Effect

Question Statement:

Nuclear radiation emitted from a Co60 radioactive source is detected by a photomultiplier tube (PMT) coupled to a scintillator crystal. Which of the following option(s) is/are correct?

Options:

  • (A) \gamma radiation from Co60 will directly hit the photocathode of the PMT without interacting with the scintillator crystal and produce a signal
  • (B) \beta radiation from Co60 source interacts with the scintillator crystal, producing \gamma radiation, which will hit the photocathode of the PMT and produce a signal
  • (C) A mu-metal shield is put all around the PMT to nullify the effect of external electric fields
  • (D) A mu -metal shield is put all around the PMT to nullify the effect of external magnetic fields

Official Answer Key:

B;D

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2025 Q.29)** **1. Radiation Detection & Photomultiplier Tubes (PMTs)**: - Detection of ionizing radiation from a $^{60}\text{Co}$ radioisotope source using a scintillation detector coupled to a PMT. **2. Detailed Analysis of Statements (MSQ)**: - **(A) False**: Photons from $^{60}\text{Co}$ interact predominantly via photoelectric effect / Compton scattering inside the dense scintillator crystal, producing visible scintillation light rather than direct photocathode detection. - **(B) Beta radiation interaction producing optical photons [TRUE]**: - $^{60}\text{Co}$ decays via $\beta^-$ emission ($E_{\max} = 0.318\text{ MeV}$) followed by cascade $\gamma$ emissions ($1.17\text{ MeV}$ and $1.33\text{ MeV}$). - Charged $\beta$ particles deposit kinetic energy inside the scintillator crystal through electronic ionization and excitation, which de-excite by emitting scintillation photons that strike the PMT photocathode. - **(C) False**: Mu-metal shields against magnetic fields, not electrostatic fields. - **(D) Mu-metal shielding against magnetic fields [TRUE]**: - PMTs operate by accelerating secondary electrons across a series of dynodes at high voltage. - Stray external magnetic fields (even Earth's magnetic field $\sim 0.5\text{ G}$) bend low-energy electron trajectories away from dynode collection apertures, drastically degrading gain. - A cylindrical **mu-metal shield** (high magnetic permeability $\mu_r \sim 10^5$) channels magnetic flux lines around the tube, shielding the dynode cascade. **3. Official Verification**: The verified official IIT answer is **Options (B) and (D)** (`['B', 'D']`).

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