GATE PH 2025 • Q26 MSQ • 1 Mark

Section 5: Thermodynamics and Statistical Physics

Blackbody radiation & Phase transitions

Subtopic: First and Second Order Phase Transitions

Question Statement:

A schematic Pressure-Temperature diagram of water is shown in the figure. Which of the following option(s) is/are correct?

Options:

  • (A) Clausius-Clapeyron equation is valid across the melting curve and the vaporization curve
  • (B) Melting curve has the highest slope
  • (C) The critical point exists only for the vaporization curve
  • (D) Clausius-Clapeyron equation is not valid across the m elting curve and the vaporization curve

Official Answer Key:

A;B;C

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2025 Q.26)** **1. Thermodynamics of Phase Transitions**: - The pressure-temperature ($P-T$) phase diagram of water displays the coexistence curves between solid (ice), liquid (water), and gas (vapor). **2. Detailed Analysis of Statements (MSQ)**: - **(A) Clausius-Clapeyron equation is valid across melting and vaporization curves [TRUE]**: - The Clausius-Clapeyron equation: $\frac{dP}{dT} = \frac{L}{T \Delta V}$ is the exact thermodynamic relationship governing all first-order phase transitions where latent heat $L$ and volume discontinuity $\Delta V$ are non-zero. It applies equally to melting, vaporization, and sublimation curves. - **(B) Melting curve has the highest slope [TRUE]**: - For melting: $\Delta V_{\text{fus}} = V_{\text{liquid}} - V_{\text{solid}}$ is extraordinarily small compared to the huge volume change of vaporization $\Delta V_{\text{vap}} \approx V_{\text{vapor}}$. - Since $\frac{dP}{dT} \propto \frac{1}{\Delta V}$, the extremely small volume change makes $\left|\frac{dP}{dT}\right|_{\text{melting}}$ vastly steeper (highest magnitude slope) than the vaporization curve. - **(C) The critical point exists only for the vaporization curve [TRUE]**: - Beyond the liquid-gas critical point ($T_c = 647\text{ K}, P_c = 22.06\text{ MPa}$), liquid and gas merge continuously into a single supercritical fluid phase. - Solid-liquid transitions have broken crystalline translational symmetry, so the melting curve never terminates at a critical point and continues indefinitely at high pressures. - **(D) False**: Contradicts statement (A). **3. Official Verification**: The verified official IIT answer is **Options (A), (B), and (C)** (`['A', 'B', 'C']`).

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