GATE PH 2025 • Q14 MCQ • 1 Mark

Section 2: Classical Mechanics

Central force problem

Subtopic: Rutherford Scattering Cross Section

Question Statement:

A particle is scattered from a potential V(r ) = gš›æ3(r ), where g is a positive constant. Using the first Born approximation, the angular (šœƒ, \phi) dependence of differential scattering cross section dšœŽ dĪ© is

Options:

  • (A) Independent of šœƒ but dependent on \phi
  • (B) Dependent on šœƒ but independent of \phi
  • (C) Dependent on both šœƒ and \phi
  • (D) Independent of both šœƒ and \phi

Official Answer Key:

D

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2025 Q.14)** **1. Quantum Scattering Theory (Born Approximation)**: - **Scattering Potential**: $V(\vec{r}) = g\delta^3(\vec{r})$, where $g$ is a positive constant. - **First Born Approximation**: The scattering amplitude $f(\theta, \phi)$ is proportional to the 3-dimensional spatial Fourier transform of $V(\vec{r})$: $f(\theta, \phi) = -\frac{m}{2\pi\hbar^2} \int V(\vec{r}) e^{-i\vec{q}\cdot\vec{r}} d^3r$ where $\vec{q} = \vec{k}_f - \vec{k}_i$ is the momentum transfer vector. **2. Analytical Evaluation**: - Substitute the delta function potential: $f(\theta, \phi) = -\frac{m}{2\pi\hbar^2} \int g\delta^3(\vec{r}) e^{-i\vec{q}\cdot\vec{r}} d^3r = -\frac{mg}{2\pi\hbar^2} e^{-i\vec{q}\cdot\vec{0}} = -\frac{mg}{2\pi\hbar^2}$ - Notice that $f(\theta, \phi)$ is a pure constant, entirely independent of scattering angles $\theta$ and $\phi$. - Differential cross section: $\frac{d\sigma}{d\Omega} = |f(\theta, \phi)|^2 = \left(\frac{mg}{2\pi\hbar^2}\right)^2 = \text{constant}$ - Therefore, the differential scattering cross section is **independent of both $\theta$ and $\phi$** (pure isotropic s-wave scattering). **3. Official Verification**: The verified official IIT answer is **Option (D)** (`Independent of both šœƒ and šœ™`).

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