GATE PH 2022 • Q40 MCQ • 2 Marks

Section 1: Mathematical Physics

Linear Algebra & Vector Calculus

Subtopic: Vector Differential Operators (Grad, Div, Curl)

Question Statement:

In cylindrical coordinates (s, šœ‘, z), which of the following is a Hermitian operator?

Options:

  • (A) 1 i šœ• šœ•s
  • (B) 1 i \left( šœ• šœ•s + 1 s\right)
  • (C) 1 i \left( šœ• šœ•s + 1 2s\right)
  • (D) \left( šœ• šœ•s + 1 s\right)

Official Answer Key:

C

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2022 Q.40)** **1. Quantum Operator Hermiticity in Curvilinear Coordinates**: - In cylindrical coordinates $(s, \phi, z)$, the volume element is: $d^3r = s\, ds\, d\phi\, dz$ - An operator $\hat{A}$ acting on radial coordinate $s$ is Hermitian if: $\int_0^\infty s\, ds\, \psi^*(s) [\hat{A} \phi(s)] = \int_0^\infty s\, ds\, [\hat{A} \psi(s)]^* \phi(s)$ **2. Step-by-Step Integration by Parts**: - Let $\hat{p}_s = \frac{1}{i}\left(\frac{\partial}{\partial s} + f(s)\right)$. - Compute the inner product: $\int_0^\infty s \psi^* \frac{1}{i}\frac{\partial \phi}{\partial s}\, ds = \left[ \frac{s\psi^*\phi}{i} \right]_0^\infty - \frac{1}{i} \int_0^\infty \frac{\partial(s\psi^*)}{\partial s} \phi\, ds$ - Using product rule on $\frac{\partial(s\psi^*)}{\partial s} = \psi^* + s\frac{\partial\psi^*}{\partial s}$: $= -\frac{1}{i}\int_0^\infty \psi^* \phi\, ds - \frac{1}{i}\int_0^\infty s \frac{\partial\psi^*}{\partial s}\phi\, ds$ $= \int_0^\infty s\, ds \left[\left(\frac{1}{i}\frac{\partial\psi}{\partial s}\right)^* - \frac{1}{is} \psi^*\right] \phi$ - To balance the extra term $-\frac{1}{is}$, the symmetric Hermitian radial momentum operator requires adding half of the metric divergence $\frac{1}{2s}$: $\hat{p}_s = \frac{1}{i}\left(\frac{\partial}{\partial s} + \frac{1}{2s}\right)$ **3. Official Verification**: The verified official IIT Master Answer is **Option (C)** (`1/i (\partial/\partial s + 1/(2s))`).

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