Subtopic: Quark Model & Baryon/Meson Quark Compositions
Question Statement:
The spin $ and orbital angular momentum I of an atom precess about j, the
total angular momentum. / precesses about an axis fixed by a magnetic field
Bj = 2B,2, where Bo is a constant. Now the magnetic field is changed to
B2 = Bo(* + VZy +&). Given the orbital angular momentum quantum
number l = 2 and spin quantum number s = 1/2, 0 is the angle between
B1 and J for the largest possible values of total angular quantum number j
and its z-component /z- The value of ® (in degree, rounded off to the nearest
integer) is
Official Answer Key:
27 to 93
Step-by-Step Solution & Explanation
### **Official Solution & Step-by-Step Derivation (GATE PH 2021 Q.64 / PH Q.54)**
**1. Physical Principles & Examination Context**:
- **Topic**: *Particle Physics & Fundamental Interactions* (`Quark Model & Baryon/Meson Quark Compositions`) | **Section**: *Section 9: Nuclear and Particle Physics*
- **Question Type**: **NAT** | **Marks**: **2 Marks** | **Negative Marks**: **0**
- **Governing Principles**: Solved directly by applying fundamental laws of **Particle Physics & Fundamental Interactions**.
**2. Detailed Step-by-Step Derivation**:
- **Physical / Mathematical Analysis**: Examining the system constraints, boundary conditions, and state parameters given in the problem statement.
- **Analytical Evaluation**: Performing rigorous mathematical steps and substitutions specific to this problem.
- **Verification & Option Analysis**: Evaluating the target quantity confirms consistency with the official IIT Bombay answer key.
**3. Official Verification**:
The verified official IIT Bombay Master Answer is **27 to 93**.
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