GATE PH 2020 • Q5 MCQ • 1 Mark

General Aptitude

Quantitative Aptitude

Subtopic: Percentages, Ratios & Proportions

Question Statement:

Define [x] as the greatest integer less than or equal to x, for each x ∈ (-∞, ∞). If y = [x], then area under y for x ∈ [1, 4] is (A) 1 (B) 3 (C) 4 (D) 6

Options:

  • (A) 1
  • (B) 3
  • (C) 4
  • (D) 6

Official Answer Key:

D

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2020 Q.5 / GA Q.5)** **1. Mathematical Formulation**: - The greatest integer function $y = [x]$ is a piecewise constant step function. - The area under the curve from $x = 1$ to $x = 4$ is given by the definite integral: $\text{Area} = \int_{1}^{4} [x] \, dx$ **2. Step-by-Step Piecewise Integration**: - Splitting the integral across consecutive unit intervals: $\text{Area} = \int_{1}^{2} [x] \, dx + \int_{2}^{3} [x] \, dx + \int_{3}^{4} [x] \, dx$ - For $x \in [1, 2)$, $[x] = 1 \implies \int_{1}^{2} 1 \, dx = 1 \times (2 - 1) = 1$ - For $x \in [2, 3)$, $[x] = 2 \implies \int_{2}^{3} 2 \, dx = 2 \times (3 - 2) = 2$ - For $x \in [3, 4)$, $[x] = 3 \implies \int_{3}^{4} 3 \, dx = 3 \times (4 - 3) = 3$ - Summing the areas: $\text{Area} = 1 + 2 + 3 = 6$ **3. Official Verification**: The verified official IIT Delhi Master Answer is **Option (D)** (`6`).

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