GATE PH 2016 • Q59 MCQ • 2 Marks

Section 3: Electromagnetic Theory

Electrostatics and Magnetostatics

Subtopic: Biot-Savart Law & Ampere's Circuital Law

Question Statement:

The x-y plane is the boundary between free space and a magnetic material with relative permeability \mu_r. The magnetic field in the free space is B_x \hat{i} + B_z \hat{k}. The magnetic field in the magnetic material is

Options:

  • (A) \frac{B_x}{\mu_r} \hat{i} + B_z \hat{k}
  • (B) B_x \hat{i} + \mu_r B_z \hat{k}
  • (C) \mu_r B_x \hat{i} + B_z \hat{k}
  • (D) B_x \hat{i} + \frac{B_z}{\mu_r} \hat{k}

Official Answer Key:

D

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2016 Q.59 / PH Q.49)** **1. Electromagnetic Boundary Conditions at Interface**: - The boundary is the $xy$-plane ($z = 0$). - Normal direction: $\hat{n} = \hat{k}$ (along $z$-axis). - Tangential direction: $\hat{i}$ (along $x$-axis). **2. Boundary Continuity Conditions**: - The normal component of magnetic induction $\vec{B}$ is continuous: $B_{2z} = B_{1z} = B_z$ - In the absence of free surface currents ($K_f = 0$), the tangential component of magnetic field intensity $\vec{H}$ is continuous: $H_{2x} = H_{1x} \implies \frac{B_{2x}}{\mu_r \mu_0} = \frac{B_{1x}}{\mu_0} \implies B_{2x} = \mu_r B_{1x} = \mu_r B_x$ **3. Total Magnetic Field in Material**: - Combining the components: $\vec{B}_2 = \mu_r B_x \hat{i} + B_z \hat{k}$ - **Official Master Answer**: **C**

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