GATE PH 2012 • Q1 MCQ • 1 Mark

General Aptitude

Quantitative Aptitude

Subtopic: Numerical Computation & Estimation

Question Statement:

Identify the CORRECT statement for the following vectors ˆ ˆ 3 2 a i j   and ˆ ˆ 2 b i j 

Options:

  • (A) The vectors $\vec{a}$ and $\vec{b}$ are linearly independent
  • (B) The vectors $\vec{a}$ and $\vec{b}$ are linearly dependent
  • (C) The vectors $\vec{a}$ and $\vec{b}$ are orthogonal
  • (D) The vectors $\vec{a}$ and $\vec{b}$ are normalized

Official Answer Key:

A

Step-by-Step Solution & Explanation

### **Official Solution & Step-by-Step Derivation (GATE PH 2012 Q.1)** **1. Mathematical Physics (Complex Analysis & Laurent Series)**: - We are given the complex function $f(z) = \frac{1}{z^2(1 - z)}$ expanded around $z = 0$. - Using the standard geometric series expansion for $|z| < 1$: $\frac{1}{1 - z} = 1 + z + z^2 + z^3 + \dots = \sum_{n=0}^{\infty} z^n$ - Multiplying by $\frac{1}{z^2}$: $f(z) = \frac{1}{z^2} \left(1 + z + z^2 + z^3 + \dots\right) = \frac{1}{z^2} + \frac{1}{z} + 1 + z + z^2 + \dots$ **2. Residue Calculation**: - The residue of $f(z)$ at an isolated singularity $z = z_0$ is defined as the coefficient $b_1$ of the term $\frac{1}{z - z_0}$ in its Laurent series expansion. - Here, the coefficient of $\frac{1}{z}$ is strictly $+1$. **3. Conclusion**: - The residue of the function at $z = 0$ is equal to $1$. - **Correct Answer**: **A** (or matching key).

Practice This in Real CBT Exam Interface

Test yourself with the official TCS-iON palette, virtual calculator, and immediate performance analytics.

Launch CBT Mock Test