Question Bank NAT • 2 Marks Section 5: Thermodynamics & Statistical Physics Blackbody radiation

QB_PH_126: Blackbody radiation

Question Statement

The peak wavelength of the cosmic microwave background is $\lambda_{max} = 1.06\text{ mm}$. With $b = 2.898 \times 10^{-3}\text{ m}\cdot\text{K}$, what is the CMB temperature in Kelvin (rounded to two decimal places)?
Correct Answer
2.7, 2.75
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $T = b / \lambda_{max} = (2.898 \times 10^{-3}) / (1.06 \times 10^{-3}) \approx 2.73\text{ K}$.
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