Question Bank NAT • 1 Mark Section 3: Electromagnetic Theory Electromagnetic Theory - Module 4

QB_PH_070: Electromagnetic Theory - Module 4

Question Statement

Light in air ($n_1 = 1$) is incident on glass with refractive index $n_2 = \sqrt{3}$. The Brewster angle in degrees is:
Correct Answer
60, 60
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $\tan(\theta_B) = n_2 / n_1 = \sqrt{3} \implies \theta_B = 60^\circ$.
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