Question Bank NAT • 2 Marks Section 3: Electromagnetic Theory Electromagnetic Theory - Module 4

QB_PH_068: Electromagnetic Theory - Module 4

Question Statement

A parallel-plate capacitor of circular plate radius $R = 0.1\text{ m}$ has $\frac{dE}{dt} = 10^{12}\text{ V}/(\text{m}\cdot\text{s})$. The displacement current in Amperes is (use $\epsilon_0 = 8.854 \times 10^{-12}\text{ F/m}$):
Correct Answer
0.27, 0.29
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $I_d = \epsilon_0 A \frac{dE}{dt} = 8.854 \times 10^{-12} \times \pi(0.1)^2 \times 10^{12} \approx 0.278\text{ A}$.
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