Question Bank NAT • 1 Mark Section 2: Classical Mechanics Special theory of relativity

QB_PH_057: Special theory of relativity

Question Statement

Two events occur at $(x_1, t_1) = (0, 0)$ and $(x_2, t_2) = (4\text{ m}, 5\text{ ns})$. With $c = 0.3\text{ m/ns}$, the interval $s^2 = c^2 \Delta t^2 - \Delta x^2$ in $\text{m}^2$ is:
Correct Answer
-13.75, -13.75
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $c \Delta t = 1.5\text{ m} \implies s^2 = (1.5)^2 - 4^2 = 2.25 - 16 = -13.75\text{ m}^2$.
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