Question Bank MCQ • 2 Marks Section 2: Classical Mechanics Special theory of relativity

QB_PH_041: Special theory of relativity

Question Statement

A light source of frequency $\nu_0$ moves directly away from a stationary observer with speed $v = 0.6c$. The frequency detected by the observer is:
(A) 0.5 \nu_0
(B) 2.0 \nu_0
(C) 0.8 \nu_0
(D) 1.25 \nu_0
Correct Answer
A
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: $\nu = \nu_0 \sqrt{\frac{1 - 0.6}{1 + 0.6}} = \nu_0 \sqrt{\frac{0.4}{1.6}} = 0.5 \nu_0$.
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