Question Bank MCQ • 1 Mark Section 1: Mathematical Physics Complex analysis

QB_PH_029: Complex analysis

Question Statement

The multivalued function $f(z) = \sqrt{z^2 - 1}$ has branch points at:
(A) z = 1 \text{ and } z = -1
(B) z = 0 \text{ only}
(C) z = i \text{ and } z = -i
(D) No branch points
Correct Answer
A
Verified Key

Step-by-Step KaTeX Derivation & Detailed Explanation

### Solution: Roots of $z^2 - 1 = 0$ are $z = \pm 1$.
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